(8x+3)^2=(3x-7)(8x+3)

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Solution for (8x+3)^2=(3x-7)(8x+3) equation: 



(8x+3)^2=(3x-7)(8x+3)

We move all terms to the left:

(8x+3)^2-((3x-7)(8x+3))=0

We multiply parentheses ..

-((+24x^2+9x-56x-21))+(8x+3)^2=0



We calculate terms in parentheses: -((+24x^2+9x-56x-21)), so:

(+24x^2+9x-56x-21)

We get rid of parentheses

24x^2+9x-56x-21

We add all the numbers together, and all the variables

24x^2-47x-21

Back to the equation:

-(24x^2-47x-21)



We get rid of parentheses

-24x^2+47x+(8x+3)^2+21=0

We move all terms containing x to the left, all other terms to the right

-24x^2+47x+(8x+3)^2=-21

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